A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is an even number
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Correct Answer: Option C
Explanation:
n(even numbers between 10 and 20 inclusive) = 6
n(numbers between 10 and 20) = 11
P(even) = \(\frac{6}{11}\)
n(even numbers between 10 and 20 inclusive) = 6
n(numbers between 10 and 20) = 11
P(even) = \(\frac{6}{11}\)