A man covered a distance of 50 miles on his first trip, on a later trip he traveled 300 miles while going 3 times as fast. His new time compared with the old distance was?
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Correct Answer: Option C
Explanation:
Let the speed of the 1st trip be x miles/hr
and the speed of the 2nd trip be 3x miles/hr
Speed = distance/time
∴ Time taken to cover a distance of 50 miles on the 1st trip
= \(\frac{50}{xhr}\)
time taken to cover a distance of 300 miles on the next trip
= \(\frac{300}{3xhr}\)
= \(\frac{100}{xhr}\)
∴the new time compared with the old time is twice as much
Let the speed of the 1st trip be x miles/hr
and the speed of the 2nd trip be 3x miles/hr
Speed = distance/time
∴ Time taken to cover a distance of 50 miles on the 1st trip
= \(\frac{50}{xhr}\)
time taken to cover a distance of 300 miles on the next trip
= \(\frac{300}{3xhr}\)
= \(\frac{100}{xhr}\)
∴the new time compared with the old time is twice as much