Evaluate ∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
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Correct Answer: Option B
Explanation:
∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\)
= \(\pi\) - 2 + c
when c is an arbitrary constant of integration
∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\)
= \(\pi\) - 2 + c
when c is an arbitrary constant of integration