For what value of x does 6 sin (2x - 25)o attain its maximum value in the range 0o \(\leq\) x \(\leq\) 180o
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Correct Answer: Option C
Explanation:
y = 6 sin (2x - 25)o
\(\frac{dy}{dx}\) = -12 cos(2x - 25o)
\(\frac{dy}{dx}\) = 0
-12 cos x (2x - 25o) = 0
= cos(2x - 25o) = 0
= 2x - 25o = cos-1(0)
= 2x - 25o
= 90o
x = \(\frac{115}{2}\)
y = 6 sin (2x - 25)o
\(\frac{dy}{dx}\) = -12 cos(2x - 25o)
\(\frac{dy}{dx}\) = 0
-12 cos x (2x - 25o) = 0
= cos(2x - 25o) = 0
= 2x - 25o = cos-1(0)
= 2x - 25o
= 90o
x = \(\frac{115}{2}\)