TQ is tangent to circle XYTR, lt; YXT = 32o, RTQ = 40o. fIND lt; YTR

TQ is tangent to circle XYTR, < YXT = 32^o, RTQ = 40^o. fIND < YTR

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A 108^o
B 121^o
C 140^o
D 148^o

Correct Answer: Option A

Explanation:

< TWR = < QTR = 40^o (alternate segment)
< TWR = < TXR = 40^o(Angles in the same segments)
< YXR = 40^o + 32^o = 72^o
< YXR + < YTR = 180^o(Supplementary)
72^o + < YTR = 180^o
< YTR = 180^o - 72^o
= 108^o

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TQ is tangent to circle XYTR, lt; YXT = 32o, RTQ = 40o. fIND lt; YTR

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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