Find the area bounded by the curve y = x(2-x). The x-axis, x = 0 and x = 2.
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Correct Answer: Option C
Explanation:
\(y = x(2-x) \Rightarrow y= 2x - x^{2};
\int^{2}_{0}(2x-x^{2} = (x^{2}-\frac{x{3}}{3})^{2}\\
solving further gives (4 - \frac{1}{3} * 8) - (0) = \frac{4}{3} sq\hspace{1 mm}unit\)
\(y = x(2-x) \Rightarrow y= 2x - x^{2};
\int^{2}_{0}(2x-x^{2} = (x^{2}-\frac{x{3}}{3})^{2}\\
solving further gives (4 - \frac{1}{3} * 8) - (0) = \frac{4}{3} sq\hspace{1 mm}unit\)