In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
PQRS is a cyclic quad^P = 180 - 110 (opp ∠s of a cyclic quad)^P = 70
In ΔPTS, ^S = ^T (base ∠s of Isc Δ)
∴^T = (180-70) / 2
= 110/2
= 55o
But ^T x(corr ∠)
∴x =55
PQRS is a cyclic quad^P = 180 - 110 (opp ∠s of a cyclic quad)^P = 70
In ΔPTS, ^S = ^T (base ∠s of Isc Δ)
∴^T = (180-70) / 2
= 110/2
= 55o
But ^T x(corr ∠)
∴x =55