Find the value of \(\int^{\pi}_{0}\frac{cos^{2}\theta-1}{sin^{2}\theta}d\theta\)
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Correct Answer: Option D
Explanation:
\(\int^{\pi}_{0}\frac{cos^{2}\theta-1}{sin^{2}\theta}d\theta = \int^{\pi}_{0}\frac{-sin^{2}\theta}{sin^{2}\theta}\\ = \int^{\pi}_{0}d\theta = -\pi\)
\(\int^{\pi}_{0}\frac{cos^{2}\theta-1}{sin^{2}\theta}d\theta = \int^{\pi}_{0}\frac{-sin^{2}\theta}{sin^{2}\theta}\\ = \int^{\pi}_{0}d\theta = -\pi\)