A bowl is designed by revolving completely the area enclosed by y = x2 - 1, y = 3 and x ≥ 0 around the axis. What is the volume of this bowl?
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Correct Answer: Option B
Explanation:
∫30 π(y+1) dy = π[y2 + y30
= π(9/2 + 3) = 15π/2
∫30 π(y+1) dy = π[y2 + y30
= π(9/2 + 3) = 15π/2