If 6Pr = 6, find the value of 6Pr+1
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Correct Answer: Option A
Explanation:
6Pr = 6 Thus r = 1
N.B 6P1 = \(\frac{\text{6!}}{\text{(6 - 1)!}}\)
= \(\frac{\text{6!}}{\text{5!}}\)
= \(\frac{6 \times \text{5!}}{\text{5!}}\) = 6
6Pr + 1 = 6P2 = \(\frac{\text{6!}}{(6 - 2)\text{!}} = \frac{6\text{!}}{\text{4!}}\)
= \(\frac{6 \times 5 \times \text{4!}}{\text{4!}}\)
= 30
6Pr = 6 Thus r = 1
N.B 6P1 = \(\frac{\text{6!}}{\text{(6 - 1)!}}\)
= \(\frac{\text{6!}}{\text{5!}}\)
= \(\frac{6 \times \text{5!}}{\text{5!}}\) = 6
6Pr + 1 = 6P2 = \(\frac{\text{6!}}{(6 - 2)\text{!}} = \frac{6\text{!}}{\text{4!}}\)
= \(\frac{6 \times 5 \times \text{4!}}{\text{4!}}\)
= 30