Evaluate \(\int \sin 3x \mathrm d x\)
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Correct Answer: Option C
Explanation:
\(\int \sin 3x \mathrm d x = - \frac{\cos 3x}{3} + c\)
= \(-\frac{1}{3} (\cos 3x) + c\)
\(\int \sin 3x \mathrm d x = - \frac{\cos 3x}{3} + c\)
= \(-\frac{1}{3} (\cos 3x) + c\)