If x varies directly as √n and x = 9 when n = 9, find x when n = (17/9)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
\(x \propto \sqrt{n}\)
\(x = k \sqrt{n}\)
\(9 = k \sqrt{9} \implies 9 = 3k\)
\(k = 3\)
\(x = 3 \sqrt{n}\)
When n = 17/9,
\(x = 3 \times \sqrt{\frac{17}{9}} = \sqrt{17}\)
\(x \propto \sqrt{n}\)
\(x = k \sqrt{n}\)
\(9 = k \sqrt{9} \implies 9 = 3k\)
\(k = 3\)
\(x = 3 \sqrt{n}\)
When n = 17/9,
\(x = 3 \times \sqrt{\frac{17}{9}} = \sqrt{17}\)