A bucket is 12 cm in diameter at the top, 8 cm in diameter at the bottom and 4 cm deep. Calculate its volume.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Volume of a frustrum with top of radius R and bottom r and height h = \(\frac{1}{3} \pi (R^{2} + Rr + r^{2})\)
V = \(\frac{1}{3} \pi \times 4 \times (6^2 + 6 \times 4 + 4^2)\)
= \(\frac{304}{3} \pi cm^{3}\)
Volume of a frustrum with top of radius R and bottom r and height h = \(\frac{1}{3} \pi (R^{2} + Rr + r^{2})\)
V = \(\frac{1}{3} \pi \times 4 \times (6^2 + 6 \times 4 + 4^2)\)
= \(\frac{304}{3} \pi cm^{3}\)