In the diagram above , XZ is the diameter of the circle XZW, with center O and radius 15/2 cm. If XY = 12 cm, find the area of the triangle XYZ
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Correct Answer: Option A
Explanation:
o ( < semi circle )
since radius = 15/2 diameter = 2 * (15/2) = 15cm
XYZ is a right angled triangle
∴ 152 = 122 + (YZ)2
225 = 144 = (YZ)2
225 - 144 = (YZ)2
81 = (YZ)2
√81 = YZ
9 = YZ
Area of ΔXYZ = 1/2bh
(1/2) * 9 * 12
9 * 6 = 54
= 54cm2
o ( < semi circle )
since radius = 15/2 diameter = 2 * (15/2) = 15cm
XYZ is a right angled triangle
∴ 152 = 122 + (YZ)2
225 = 144 = (YZ)2
225 - 144 = (YZ)2
81 = (YZ)2
√81 = YZ
9 = YZ
Area of ΔXYZ = 1/2bh
(1/2) * 9 * 12
9 * 6 = 54
= 54cm2