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Tuesday, 03 March 2026
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Determine the maximum value of y = 3x2 - x3

Determine the maximum value of y = 3x2 - x3
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  • A Zero
  • B 2
  • C 4
  • D 6
Correct Answer: Option C
Explanation:
y = 3x2 - x3
dy/dx = 6x - 3x2
as dy/dx = 0
6x - 3x2 = 0
3x (2 - x) = 0
this implies that 2 -x = 0 and 3x = 0
x = 2 (or) 0
But = dy/dx = 6x - 3x2
d2y/dx2 = 6 - 6x at x = 2
= 6 - 6(2)
= -6
y = 3x2 - x3
= 3(2)2 - 23
= 12 - 8
= 4

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