An aeroplane flies due north from airport P to Q and then flies due east R. If Q is equidistant from P and R, find the bearing of P and R
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Correct Answer: Option C
Explanation:
Since PQ = QR, Δ PQR is a right angle isosceles triangle
∴ ∠PQR = 45o
=> The bearing of P from R = 180 + 45
= 225o
Since PQ = QR, Δ PQR is a right angle isosceles triangle
∴ ∠PQR = 45o
=> The bearing of P from R = 180 + 45
= 225o