Three straight lines EF, GH and LK interest at O as shown above. If ∠ KOF = 52o and ∠ LOH = 85o, calculate the size of ∠ EOG.
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Correct Answer: Option B
Explanation:
∠ GOK = 85o (vertical opposite angle ∠ s)
∠ EOG + ∠ GOK + ∠ KOF = 180 (∠ s on a straight line)
∠ EOg + 85o + 52o = 180o
∠ EOG + 137o = 180o
∠ EOG = 43o
∠ GOK = 85o (vertical opposite angle ∠ s)
∠ EOG + ∠ GOK + ∠ KOF = 180 (∠ s on a straight line)
∠ EOg + 85o + 52o = 180o
∠ EOG + 137o = 180o
∠ EOG = 43o