If the mean of five consecutive integers is 30, find the largest of the numbers
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Correct Answer: Option C
Explanation:
Let the consecutive numbers be a, a+1, a+2, a+3, a+4
Mean = \(\frac{(a+a+1+a+2+a+3+a+4)}{5}\\
30 = \frac{5a+10}{5}\\
30 \times 5 = 5a + 10\\
5a = 150 - 10\\
5a = 140\\
a = 28 \\
∴ a + 4 = 28 + 4\\
= 32\)
Let the consecutive numbers be a, a+1, a+2, a+3, a+4
Mean = \(\frac{(a+a+1+a+2+a+3+a+4)}{5}\\
30 = \frac{5a+10}{5}\\
30 \times 5 = 5a + 10\\
5a = 150 - 10\\
5a = 140\\
a = 28 \\
∴ a + 4 = 28 + 4\\
= 32\)