Find the variance of 2x, 2x-1 and 2x+1
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
\(\sum x = 6x\\
\sum(x-\bar{x})^2 = 2\\
\bar{x} = \frac{\sum x}{n}\\
= \frac{6x}{3}\\
= 2x\\
Variance = \frac{\sum(x-\bar{x})^2}{n}\\
= \frac{2}{3}\)
\(\sum x = 6x\\
\sum(x-\bar{x})^2 = 2\\
\bar{x} = \frac{\sum x}{n}\\
= \frac{6x}{3}\\
= 2x\\
Variance = \frac{\sum(x-\bar{x})^2}{n}\\
= \frac{2}{3}\)