Evaluate \(\int_{-4}^0(1 - 2x)dx\)
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Correct Answer: Option C
Explanation:
\(\int_{-4}^0(1 - 2x)dx=[x-x^2]_{-4}^0\\= (0 - 0 + C) - (-4(-4)^2 + C)\\
= C - (-4-16+C)\\
= C-(-20+C)\\
= C+20-C\\
= 20\)
\(\int_{-4}^0(1 - 2x)dx=[x-x^2]_{-4}^0\\= (0 - 0 + C) - (-4(-4)^2 + C)\\
= C - (-4-16+C)\\
= C-(-20+C)\\
= C+20-C\\
= 20\)