If (K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\), what is the value of k?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
(K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\)
(K*6\(^1\) + 2*6\(^0\))Â 3*6\(^0\) = 3*5\(^0\)(K*5\(^1\)Â + 4*5\(^0\))
3(6K + 2) = 3(5K + 4)
6K + 2 = 5K + 4
6K - 5KÂ = 4 - 2
K = 2
(K2)\(_6\) * 3\(_6\) = 3\(_5\)(K4)\(_5\)
(K*6\(^1\) + 2*6\(^0\))Â 3*6\(^0\) = 3*5\(^0\)(K*5\(^1\)Â + 4*5\(^0\))
3(6K + 2) = 3(5K + 4)
6K + 2 = 5K + 4
6K - 5KÂ = 4 - 2
K = 2