In the diagram above, POQ is a diameter of the circle PQRS. If ∠ PSR = 145°, find x°
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Correct Answer: Option A
Explanation:
∠ PSQ = 90° (∠ in semi circle)
∠ PSQ + ∠ QSR = 145°
90 + ∠ QSR = 145
∠ QSR = 145 - 90
∠ QSR = 55°
BUt x° = ∠ QSR (∠ s in the same segment)
−x° = 55°
∠ PSQ = 90° (∠ in semi circle)
∠ PSQ + ∠ QSR = 145°
90 + ∠ QSR = 145
∠ QSR = 145 - 90
∠ QSR = 55°
BUt x° = ∠ QSR (∠ s in the same segment)
−x° = 55°