Solve the inequalities for which \(\frac{x+4}{3}-\frac{x-3}{2} < 4\)
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Correct Answer: Option B
Explanation:
\(\frac{x+4}{3}-\frac{x-3}{2} < 4\\
\frac{(2(x+4))-(3(x-3))}{6}<4\)
2(x+4) – 3(x-3) < 4 x 6
2x + 8 – 3x+9 < 24
-x + 17 < 24
-x < 24 – 17
-x < 7
x > -7
\(\frac{x+4}{3}-\frac{x-3}{2} < 4\\
\frac{(2(x+4))-(3(x-3))}{6}<4\)
2(x+4) – 3(x-3) < 4 x 6
2x + 8 – 3x+9 < 24
-x + 17 < 24
-x < 24 – 17
-x < 7
x > -7