Find y, if \(\sqrt{12}-\sqrt{147}+y\sqrt{3} = 0\)
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Correct Answer: Option A
Explanation:
\(\sqrt{12}-\sqrt{147}+y\sqrt{3} = 0\\
\sqrt{4\times 3}-\sqrt{49\times 3}+y\sqrt{3} = 0\\
2\sqrt{3}-7\sqrt{3}+y\sqrt{3} = 0\\
y\sqrt{3} = 7\sqrt{3} - 2\sqrt{3}\\
y=\frac{5\sqrt{3}}{\sqrt{3}}\\
y = 5\)
\(\sqrt{12}-\sqrt{147}+y\sqrt{3} = 0\\
\sqrt{4\times 3}-\sqrt{49\times 3}+y\sqrt{3} = 0\\
2\sqrt{3}-7\sqrt{3}+y\sqrt{3} = 0\\
y\sqrt{3} = 7\sqrt{3} - 2\sqrt{3}\\
y=\frac{5\sqrt{3}}{\sqrt{3}}\\
y = 5\)