Evaluate \(\frac{\left(\frac{3}{8}\div\frac{1}{2}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\)
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Correct Answer: Option D
Explanation:
\(\frac{\left(\frac{3}{8}\div\frac{1}{2}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{8}\times\frac{2}{1}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{4}-\frac{1}{3}\right)}{\left(\frac{1}{12}+\frac{1}{3}\right)}\\
=\left(\frac{9-4}{12}\right)\div\left(\frac{1+4}{12}\right)\\
=\left(\frac{5}{12}\right)\div\left(\frac{5}{12}\right)\\
=\frac{5}{12}\times\frac{12}{5}\\
=1\)
\(\frac{\left(\frac{3}{8}\div\frac{1}{2}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{8}\times\frac{2}{1}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{4}-\frac{1}{3}\right)}{\left(\frac{1}{12}+\frac{1}{3}\right)}\\
=\left(\frac{9-4}{12}\right)\div\left(\frac{1+4}{12}\right)\\
=\left(\frac{5}{12}\right)\div\left(\frac{5}{12}\right)\\
=\frac{5}{12}\times\frac{12}{5}\\
=1\)