If p varies inversely as the square of q and p=8 when q=4, find q when p =32
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Correct Answer: Option D
Explanation:
p ∠1/q
p = k/q
K = q\(^2\)p
= 4\(^2\)(8)
∴p = 128/q
32 = 128/q
q\(^2\) = 128/32
q\(^2\) = 4
q = √4 = \(\pm\) 2
p ∠1/q
p = k/q
K = q\(^2\)p
= 4\(^2\)(8)
∴p = 128/q
32 = 128/q
q\(^2\) = 128/32
q\(^2\) = 4
q = √4 = \(\pm\) 2