Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
3X + 2Y + 1 = 0
2Y = -3X - 1
\(\frac{-3}{2}X - \frac{1}{2}\)
Gradient of 3X + 2Y +1 = 0 is -3/2
Gradient of a line perpendicular to 3X + 2Y + 1 = 0
\(=-1 \div \frac{3}{2}\\
=-1 \times \frac{-2}{3}=\frac{2}{3}\)
3X + 2Y + 1 = 0
2Y = -3X - 1
\(\frac{-3}{2}X - \frac{1}{2}\)
Gradient of 3X + 2Y +1 = 0 is -3/2
Gradient of a line perpendicular to 3X + 2Y + 1 = 0
\(=-1 \div \frac{3}{2}\\
=-1 \times \frac{-2}{3}=\frac{2}{3}\)