If y varies directly as the square root of x and y = 3 when x = 16. Calculate y when x = 64
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Correct Answer: Option B
Explanation:
y ∠√xy = K√x
K = y/√x = 3/√16
= 3/4y = 3/4√x
= 3/4√64 when x = 64
= 3/4 x 8/1
= 6
y ∠√xy = K√x
K = y/√x = 3/√16
= 3/4y = 3/4√x
= 3/4√64 when x = 64
= 3/4 x 8/1
= 6