If the area of ΔPQR above is 12√3 cm2, find the value of q?
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Correct Answer: Option A
Explanation:
Area of a triangle = 1/2 ab Sinθ
12√3 = 1/2 x 8 x q sin 60
12√3 = 4 x q x √3/2
12√3 = 2q√3
q = 6
Area of a triangle = 1/2 ab Sinθ
12√3 = 1/2 x 8 x q sin 60
12√3 = 4 x q x √3/2
12√3 = 2q√3
| 2√3 |
q = 6