The solution of the equation \(x^{2}-2 x=8\) is ____________
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Correct Answer: Option B
Explanation:
$$
\begin{array}{l}
x^{2}-2 x-8=0 \\
x^{2}-4 x+2 x-8=0 \\
x(x-4)+2(x-4)=0 \\
(x+2)(x-4)=0 \\
x=-2 \text { or } 4
\end{array}
$$
$$
\begin{array}{l}
x^{2}-2 x-8=0 \\
x^{2}-4 x+2 x-8=0 \\
x(x-4)+2(x-4)=0 \\
(x+2)(x-4)=0 \\
x=-2 \text { or } 4
\end{array}
$$