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Find ∫(sin x + 2)dx

Find ∫(sin x + 2)dx
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
  • A Cos x + x2 + K
  • B Cos x 2x + K
  • C -cos x + x2 + K
  • D -cos x + 2x + K
Correct Answer: Option D
Explanation:
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K

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