A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
Actual length of rope = 1.25mMeasured length of rope = 1.26merror = (1.26 - 1.25)m - 0.01mPercentage error = \(\frac{error}{\text{actual length}}\) x 100%= \(\frac{0.01}{1.25}\) x 100% = 0.08%
Actual length of rope = 1.25mMeasured length of rope = 1.26merror = (1.26 - 1.25)m - 0.01mPercentage error = \(\frac{error}{\text{actual length}}\) x 100%= \(\frac{0.01}{1.25}\) x 100% = 0.08%