Find the standard deviation of 2, 3, 5 and 6
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Correct Answer: Option D
Explanation:
\(\begin{array}& x & x - \bar{x} & (x - \bar{x})^2 \\2 & -2 & 4 \\ 3 & -1 & 1 \\ 5 & 1 & 1 \\ 6 & 2 & 4\\ \hline \sum x = 16 & & \sum (x - \bar{x}^2) = 0 \end{array}\)
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\(\bar{x}\) = \(\frac{\sum x }{N}\)
= \(\frac{16}{4}\)
= 4
S = \(\sqrt{\frac {(x - \bar{x})^2}{N}}\)
= \(\sqrt{\frac {(10)}{4}}\)
= \(\sqrt{\frac {(5)}{2}}\)
\(\begin{array}& x & x - \bar{x} & (x - \bar{x})^2 \\2 & -2 & 4 \\ 3 & -1 & 1 \\ 5 & 1 & 1 \\ 6 & 2 & 4\\ \hline \sum x = 16 & & \sum (x - \bar{x}^2) = 0 \end{array}\)
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\(\bar{x}\) = \(\frac{\sum x }{N}\)
= \(\frac{16}{4}\)
= 4
S = \(\sqrt{\frac {(x - \bar{x})^2}{N}}\)
= \(\sqrt{\frac {(10)}{4}}\)
= \(\sqrt{\frac {(5)}{2}}\)