A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.
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Correct Answer: Option B
Explanation:
tan\(\theta\) = \(\frac{100}{100}\) = 1
\(\theta\) = tan-1(1) = 45o
The bearing of x from z is N45oE or 135o
tan\(\theta\) = \(\frac{100}{100}\) = 1
\(\theta\) = tan-1(1) = 45o
The bearing of x from z is N45oE or 135o