Evaluate \(\int^{1}_{2}\)(3 - 2x)dx
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Correct Answer: Option C
Explanation:
\(\int^{1}_{0}\)(3 - 2x)dx
[3x - x\(^2\)]\(_{0} ^{1}\)
[3(1) - (1)\(^2\)] - [3(0) - (0)\(^2\)]
(3 - 1) - (0 - 0) = 2 - 0
= 2
\(\int^{1}_{0}\)(3 - 2x)dx
[3x - x\(^2\)]\(_{0} ^{1}\)
[3(1) - (1)\(^2\)] - [3(0) - (0)\(^2\)]
(3 - 1) - (0 - 0) = 2 - 0
= 2