The locus of a point equidistant from the intersection of lines 3x - 7y + 7 = 0 and 4x - 6y + 1 = 0 is a
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
The locus of point equidistant from the point of intersection of the two lines is a circle with their points of intersection as the center.
The locus of point equidistant from the point of intersection of the two lines is a circle with their points of intersection as the center.