Evaluate \(\int^2_1(x^2 - 4x)dx\)
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Correct Answer: Option D
Explanation:
\(\int^2_1(x^2 - 4x)dx\)
\((\frac{x^3}{3} - \frac{4x^2}{2})\)
substituting integrate values
\([\frac{8}{3} - \frac{4 \times 4}{2}] - [\frac{1}{2} - 2]\)
= \(-\frac{11}{3}\)
\(\int^2_1(x^2 - 4x)dx\)
\((\frac{x^3}{3} - \frac{4x^2}{2})\)
substituting integrate values
\([\frac{8}{3} - \frac{4 \times 4}{2}] - [\frac{1}{2} - 2]\)
= \(-\frac{11}{3}\)