The probability that a student passes a physics test is \(\frac{2}{3}\). If he takes three physics tests, what is the probability that he passes two of the tests?
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Correct Answer: Option C
Explanation:
Pass(P) = \(\frac{2}{3}\), Fail(F) = \(\frac{1}{3}\)
T = P.P.F ==> \(\frac{2}{3} \times \frac{2}{3} \times \frac{1}{3}\) = \(\frac{4}{27}\)
Pass(P) = \(\frac{2}{3}\), Fail(F) = \(\frac{1}{3}\)
T = P.P.F ==> \(\frac{2}{3} \times \frac{2}{3} \times \frac{1}{3}\) = \(\frac{4}{27}\)