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A girl walks \(30 m\) from a point \(P\) on a bearing of \(040^{\circ}\) to a point Q. ...

A girl walks \(30 m\) from a point \(P\) on a bearing of \(040^{\circ}\) to a point Q. She then walks \(30 m\) on a bearing of \(140^{\circ}\) to a point \(R\). The bearing of \(R\) from \(P\) is
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  • A \(90^{\circ}\)
  • B \(50^{\circ} \quad\)
  • C \(45^{\circ}\)
  • D \(40^{\circ}\)
Correct Answer: Option A
Explanation:
From the diagram. we deduced that \(\theta=50^{\circ}\) hence, the hearing of \(R\) from \(P\) is \(50^{\circ}+40^{\circ}=90^{\circ}\)

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