Explanation:
\(41,-22,=17\)onverting all to base 10 . we have
\(4 \times x^{-1}+1 \times x^{0}-\left(2 \times x^{1}+2 \times x^{0}\right)\)
\(=1 \times x^{1}+7\)
\(=4 x+1-(2 x+2)=x+7\)
\(4 x-2 x-2+1=x+7\)
\(2 x-1=x+7 ; x=8\)ut it is required that \(x\) in base 3 , hence we have
\begin{array}{l|l}
3 & 8 \\
\hline 3 & 2 r 2 \\
0 & r 2
\end{array} \mid=22_{3}