A man walks 1km due east and then 1km due north. His displacement is
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Correct Answer: Option C
Explanation:
R = \(\sqrt{1^2 + 1^2}\) = \(\sqrt{2km}\)
\(\theta\) = tan-1 \(\frac{(1)}{1}\) = 45oC
= \(\sqrt 2\)km N 45oE
R = \(\sqrt{1^2 + 1^2}\) = \(\sqrt{2km}\)
\(\theta\) = tan-1 \(\frac{(1)}{1}\) = 45oC
= \(\sqrt 2\)km N 45oE