A piece of rubber 10cm long stretches 6mm when a load of 100N is hung from it. What is the strain?
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Correct Answer: Option C
Explanation:
Strain = \(\frac{\Delta L}{L}\)
= \(\frac{6 \times 10^{-1}}{10}\)
= 6 x 10-2
Strain = \(\frac{\Delta L}{L}\)
= \(\frac{6 \times 10^{-1}}{10}\)
= 6 x 10-2