A temperature 20°C is the same as
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Correct Answer: Option B
Explanation:
212°F ... 100°C
\(\theta\)°F ... 20°C
32°F ... 0°C
\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)
180 = 5(\(\theta\) - 32)
5\(\theta\) = 180 + 160 = 340
\(\theta\) = 68°F
212°F ... 100°C
\(\theta\)°F ... 20°C
32°F ... 0°C
\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)
180 = 5(\(\theta\) - 32)
5\(\theta\) = 180 + 160 = 340
\(\theta\) = 68°F