A 500kg car which was initially at rest travelled with an acceleration of 5m sec-2, its kinetic energy after 4 seconds was
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J