If in a simple pendulum experiment the length of the inextensible string is increased by a factor of four, its period is increased by a factor of
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Correct Answer: Option E
Explanation:
In simple pendulum, T = 2\(\pi\)\(\sqrt\frac{L}{g}\)
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{L_2}\) but, L2 = 4L1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{4L_1}\)
T2 = 4T1
In simple pendulum, T = 2\(\pi\)\(\sqrt\frac{L}{g}\)
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{L_2}\) but, L2 = 4L1
\(\frac{T_2}{T_1}\) = \(\sqrt\frac{L_1}{4L_1}\)
T2 = 4T1