An electric cell has an internal resistance of 2 ohms. A current of 0.5A is found to flow when a resistor of 5 ohms resistance is connected across it. What is the electromotive force of the cell?
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Correct Answer: Option B
Explanation:
E.m.f. = I(R + r) = 0.5(2+5) = 3.5 volts
E.m.f. = I(R + r) = 0.5(2+5) = 3.5 volts