The bulb of a motorcycle head-lamp is marked 40W, 6V. The resistance of the filament when it is switched on is
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Correct Answer: Option E
Explanation:
Power \(\frac{V^2}{R}\)
40 = \(\frac{6 \times 6}{r}\)
R = \(\frac{36}{40}\)\(\Omega\)
Power \(\frac{V^2}{R}\)
40 = \(\frac{6 \times 6}{r}\)
R = \(\frac{36}{40}\)\(\Omega\)