The speed of light in air is 3 x 108ms-1. If the refractive index of light from air-to-water is \(\frac{4}{3}\), then which of the following is the correct value of the speed of light in water?
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Correct Answer: Option B
Explanation:
Air to water = \(\frac{\text{speed in air}}{\text{speed in water}}\)
\(\frac{4}{3}\) = \(\frac{3 \times 10^8}{V}\)
4V = 3(3 x 108)
V = \(\frac{3(3 \times 10^8)}{4}\)
V = 2.25 x 108ms-1
Air to water = \(\frac{\text{speed in air}}{\text{speed in water}}\)
\(\frac{4}{3}\) = \(\frac{3 \times 10^8}{V}\)
4V = 3(3 x 108)
V = \(\frac{3(3 \times 10^8)}{4}\)
V = 2.25 x 108ms-1