A milliameter of resistance 5\(\Omega\) and full scale deflection of 5m A is to used to measure a potential difference of 50 V. The resistance of the multiplier should be
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Correct Answer: Option D
Explanation:
V = IR
50 = 50 x 10-3 (5 + R)
R = 995\(\Omega\)
V = IR
50 = 50 x 10-3 (5 + R)
R = 995\(\Omega\)