The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
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Correct Answer: Option E
Explanation:
Pressure in liquid = e x h x g
Pressure in solid = \(\frac{force}{area}\)
\(\frac{force}{area}\) = e x h x g
force = 0.5 x 10 x 200 x 1.03
= 1030N
Pressure in liquid = e x h x g
Pressure in solid = \(\frac{force}{area}\)
\(\frac{force}{area}\) = e x h x g
force = 0.5 x 10 x 200 x 1.03
= 1030N